A body weighing 1 kg begins to move from coordinate 10m with an initial speed of 10m / s

A body weighing 1 kg begins to move from coordinate 10m with an initial speed of 10m / s under the action of a force of 1kN. Write the equation of body motion.

Data: m (mass of a moving body) = 1 kg; x0 (start coordinate) = 10 m; V0 (initial speed) = 10 m / s; F (acting force) = 1 kN = 1000 N.

Since the equation of motion of any body can be represented in the form: x (t) = x0 + V * t + a * t ^ 2/2, the equation of motion of the taken body will take the form: x (t) = x0 + V * t + ( F / m) * t ^ 2/2 = 10 + 10 * t + (1000/1) * t ^ 2/2 = 10 + 10t + 500t ^ 2.

Answer: The equation of motion of the taken body has the form: x (t) = 10 + 10t + 500t ^ 2.