A body weighing 1 kg is evenly pulled upwards along an inclined plane with a lifting angle of 60

A body weighing 1 kg is evenly pulled upwards along an inclined plane with a lifting angle of 60 degrees without friction. Determine the pulling force.

We place the coordinate system in this way: the origin of coordinates O is at the center of gravity of the body, we direct the abscissa axis Ox along the movement of the body, and the ordinate axis Oy will be directed upward, perpendicular to Ox. Then the projections (vector coordinates) of the force of gravity on these axes will be Ftyazh.x = – m ∙ g ∙ sinα and Ftyazh.y = – m ∙ g ∙ cosα, where the proportionality coefficient g = 9.8 N / kg. The projections of the traction force applied to the body will be Fх and Fу = 0. According to the condition, along an inclined plane with an ascent angle α = 60 degrees without friction, a body with a mass of m = 1 kg is evenly pulled upwards, which means that the projection of the resultant on the ОХ axis will be equal to zero , since the acceleration is zero, then: Fх + Ftyazh.х = 0; Fх + (- m ∙ g ∙ sinα) = 0; Fх = m ∙ g ∙ sinα; Fх = – 1 ∙ 9.8 ∙ sin30 ° = 4.9 N.
Answer: 4.9 N.