A body weighing 1 kg moves with an acceleration of 0.25 m / s2 along the horizontal plane.

A body weighing 1 kg moves with an acceleration of 0.25 m / s2 along the horizontal plane. The coefficient of friction against the surface is 0.1. Determine the force acting on the body.

To find the force imparting acceleration to a given body, we project all the forces onto the OX axis: m * a = F – Ftr, whence F = Ftr + m * a = μ * m * g + m * a.

Variables: μ – coefficient of friction against the surface (μ = 0.1); m is the mass of a moving body (m = 1 kg); g – acceleration due to gravity (g ≈ 10 m / s2); a – acquired acceleration (a = 0.25 m / s2).

Calculation: F = μ * m * g + m * a = 0.1 * 1 * 10 + 1 * 0.25 = 1.25 N.

Answer: The effective force is 1.25 N.




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