A body weighing 10 kg falls from a height of 1 m with an acceleration of 8 m / s. Find changes in the body’s momentum.

Data: m (mass of a rapidly falling body) = 10 kg; h (original height) = 1 m; a (acceleration) = 8 m / s.

1) The duration of the fall: h = S = a * t ^ 2/2, whence we express: t = √ (2h / a) = √ (2 * 1/8) = 0.5 s.

2) Velocity at the end of the fall: V = a * t = 8 * 0.5 = 4 m / s.

3) Change in momentum: ΔP = m * ΔV = 10 * (4 – 0) = 40 kg * m / s.

Answer: The impulse of the falling body has changed (increased) by 40 kg * m / s.