A body weighing 10 kg in the horizontal plane was moved to a distance of 5 m, and then raised to a height of 5 m.

A body weighing 10 kg in the horizontal plane was moved to a distance of 5 m, and then raised to a height of 5 m. What is the work of gravity at each stage of the movement?

When driving horizontally:
A1 = Ft * S * cos (F, S), Ft is the force of gravity, S is the displacement of the body, cos (F, S) = cos 90 = 0 (since the vector of gravity will make an angle of 90º with the vector of displacement).
A1 = Ft * S * cos (F, S) = Ft * S * 0 = 0 J.
When lifting:
A2 = F * S * cos (F, S), where F = m * g (m is the mass of the body (m = 10 kg), g is the acceleration of gravity (g = 9.8 m / s ^ 2)), S-displacement (S = 5 m), cos (F, S) = cos 180 = -1 (the direction of gravity is opposite to the movement of the body).
A2 = F * S * cos (F, S) = -10 * 9.8 * 5 = -490 J.
Answer: A1 = 0 J, A2 = – 490 J.



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