A body weighing 10 kg is lifted evenly by 1 m. What kind of work is done in this case?

Initial data: m (body weight) = 10 kg, h (height to which the body was lifted) = 1 m.

Constants: g (acceleration due to gravity) = 10 m / s ^ 2.

The work that is done when lifting a given body can be calculated using the formulas:

A = F * S, where F is the force applied to the body (F = Ft = m * g), S (body movement) = h.

A = En2 – En2, where En2 is the potential energy at a height of 1 m (En2 = m * g * h), En1 is the potential energy at the initial height (En2 = 0).

A = m * g * h = 10 * 10 * 1 = 100 J.