A body weighing 10 kg, moving at a speed of 36 km / h, increases its speed by half the value in 10 seconds. determine under the influence of what force
Initial data: m (body weight) = 10 kg; V1 (initial speed with which the body was moving) = 36 km / h (10 m / s); V2 (final speed of the body) = 1.5V1; t (duration of body speed change) = 10 s.
1) Determine the acceleration with which the body moved: a = (V2 – V1) / t = (1.5V1 – V1) / t = 0.5V1 / t = 0.5 * 10/10 = 0.5 m / s2 …
2) Let’s calculate the force under which the body increased its speed: F = m * a = 10 * 0.5 = 5 N.
Answer: The body increased its speed under the influence of a force of 5 N.
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