A body weighing 10 kg slides off an inclined plane with an angle of inclination of 40 degrees.

A body weighing 10 kg slides off an inclined plane with an angle of inclination of 40 degrees. determine the friction force if the acceleration of the body is 2 m / s2

∠α = 40 “.

m = 10 kg.

a = 2 m / s ^ 2.

g = 9.8 m / s ^ 2.

Ftr -?

Let’s write 2 Newton’s law in projections on an inclined plane: m * a = m * g * sinα – Ftr.

Ftr = m * g * sinα – m * a.

Ftr = m * (g * sinα – a).

Ftr = 10 kg * (9.8 m / s ^ 2 * sin40 “- 2 m / s ^ 2) = 42.9 N.

Answer: the friction force is Ftr = 42.9 N.