A body weighing 10 N floats in a liquid. The volume of the displaced liquid is equal to 0.2

A body weighing 10 N floats in a liquid. The volume of the displaced liquid is equal to 0.2 of the volume of the body. What is the buoyancy force acting on the body?

Since the body floats in water, then the condition will be true for it:
Fexhaust = FTit.

Weight equals gravity.

Note that the buoyant force of the body depends on the height of the part of the body in the water, and the force of gravity depends on the entire height of the body.

This means that the following ratio of heights and forces will be true for them:

hin water / H = Fexhaust / Ftyl.
Since the volume of the displaced liquid is 0.2 of the volume of the body,
then consequently

h in water / H = 0.2

From here

Ftight = 0.2 * Ftyach = 0.2 * 10 = 2 N.

Answer: 2 N.