A body weighing 100 kg suspended on a rope and moving vertically downward at a speed of 6

A body weighing 100 kg suspended on a rope and moving vertically downward at a speed of 6 m / s stops after 4 s. Determine the pulling force of the rope when braking.

To calculate the required tensile force of the taken rope during braking, we will project all the acting forces on the OU axis: m * a = T – Fт, whence T = m * a + m * g = m * (V / t + g).

Variables and constants: m is the mass of a slowly moving body (m = 100 kg); V – initial speed of descent (V = 6 m / s); t – duration of movement (t = 4 s); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: T = m * (V / t + g) = 100 * (6/4 + 10) = 100 * 1.15 = 1150 N.

Answer: During braking, the rope pulling force was 1150 N.