A body weighing 10N is submerged in water. The weight of the displaced liquid is 6N. How is the buoyancy value?
| February 9, 2021 | education
P1 = 10 Newton – body weight in air;
P2 = 6 Newton – the weight of the displaced fluid into which the body was immersed.
It is required to determine A (Newton) – the value of the Archimedean (buoyancy) force.
According to Archimedes’ law, the weight of the displaced water is equal to the weight of the body immersed in the liquid. Then:
A = P1 – P2 = 10 – 6 = 4 Newtons.
Answer: the buoyant (Archimedean) force is 4 Newtons.
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