A body weighing 15 kg lies on a slope that makes an angle of 30 degrees with the horizon. if a horizontal force of 10 N

A body weighing 15 kg lies on a slope that makes an angle of 30 degrees with the horizon. if a horizontal force of 10 N is applied to the body, then it will move. what is the coefficient of heat of the body against the surface?

∠α = 30 °.

F = 10 N.

m = 15 kg.

g = 10 m / s2.

μ -?

According to 1 Newton’s law, for the uniform motion of a body, it is necessary that the action of forces on it be compensated.

F + Ftr + N + m * g = 0 – vector.

ОХ: F * cosα – Ftr + m * g * sinα = 0.

OU: F * sinα + N – m * g * cosα = 0.

Ftr = F * cosα + m * g * sinα.

N = m * g * cosα – F * sinα.

The friction force Ffr is determined by the formula: Ffr = μ * N.

μ = Ftr / N = (F * cosα + m * g * sinα) / (m * g * cosα – F * sinα).

μ = (10 N * cos30 ° + 15 kg * 10 m / s2 * sin30 °) / (15 kg * 10 m / s2 * cos30 ° – 10 N * sin30 °) = 0.67.

Answer: the coefficient of friction is μ = 0.67.