# A body weighing 150N is completely immersed in a liquid. The weight of the displaced liquid

**A body weighing 150N is completely immersed in a liquid. The weight of the displaced liquid is 100N. What is the Archimedes force acting on the body?**

Given:

P = 150 Newton – body weight;

P1 = 100 Newtons – the weight of the fluid displaced by the body.

It is required to determine A (Newton) – the Archimedean force acting on the body.

According to Archimedes’ law, a buoyant force acts on a body immersed in a liquid, equal to the weight of the liquid in the volume of the body immersed in it. Since, according to the condition of the problem, the body completely floats in the liquid, it means that the volume of the displaced liquid is equal to the volume of the body. That is:

A = Ro fluid * V fluid * g = m * g = P1 = 100 Newton.

Answer: the body is acted upon by an Archimedean force equal to 100 Newtons.