A body weighing 2.5 kg slides on the surface with a friction coefficient of 0.15.

A body weighing 2.5 kg slides on the surface with a friction coefficient of 0.15. Find the work of the friction force if the path traveled by the body is 3m.

To calculate the required work of the acting friction force, we apply the formula: Atr = Ffr * S = μ * N * S = μ * m * g * S.

Constants and variables: μ – coefficient of friction (μ = 0.15); m is the mass of the sliding body (m = 2.5 kg); g – acceleration due to gravity (g ≈ 10 m / s2); S – distance traveled (S = 3 m).

Calculation: Atr = μ * m * g * S = 0.15 * 2.5 * 10 * 3 = 11.25 J.

Answer: During the sliding time of the body in question, the friction force performed work equal to 11.25 J.



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