A body weighing 2 kg collided with a body weighing 4 kg before the collision, the second body was at rest after
| September 19, 2021 | education
A body weighing 2 kg collided with a body weighing 4 kg before the collision, the second body was at rest after an inelastic impact, both bodies began to move at a speed of 6 m / s at what speed did the first body move?
To calculate the speed of the first body before an inelastic impact, we will use the law of conservation of momentum: V1.2 * (m1 + m2) = V1 * m1, whence we express: V1 = V1.2 * (m1 + m2) / m1.
Variables: V1.2 – total speed of bodies (V1.2 = 6 m / s); m1 is the mass of the moving body (m1 = 2 kg); m2 is the mass of a motionless body (m2 = 4 kg).
Calculation: V1 = 6 * (2 + 4) / 2 = 18 m / s.
Answer: The first body, before the inelastic impact, was moving at a speed of 18 m / s.
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