# A body weighing 2 kg falls from a height of 10 m. The speed at the moment of touching the ground

October 9, 2021 | education

| **A body weighing 2 kg falls from a height of 10 m. The speed at the moment of touching the ground is 10 m / s. find the work of the force of air resistance.**

To find the work done by the force of air resistance, we will use the equality: Ep = Ek + Asopr, whence we express: Asopr = Ep – Ek = m * (g * h – V ^ 2/2).

Constants and variables: m – body weight (m = 2 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h – initial height (h = 10 m); V – speed at the moment of touching the ground (V = 10 m / s).

Calculation: Asopr = m * (g * h – V ^ 2/2) = 2 * (10 * 10 – 10 ^ 2/2) = 100 J.

Answer: The force of air resistance during the fall of a given body performed work of 100 J.

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