A body weighing 2 kg is acted upon by forces of 3 N and 4 N, directed perpendicular to each other.

A body weighing 2 kg is acted upon by forces of 3 N and 4 N, directed perpendicular to each other. What is the acceleration of the body?

Given:
m = 2 kg;
F1 = 3H; F2 = 4H;
Find ah?
Decision:
We use Newton’s second law:
a = F / m;
It is important that we proceed from the fact that acceleration is directly proportional to the resultant of all forces, and inversely proportional to the mass of the body, we can conclude that the modulus of the resultant l F l can be found by the Pythagorean theorem:
l F l = √ (l F1 l ^ 2 + l F2 l ^ 2);
Then, after substituting the known values, we get:
l F l = √ (3 ^ 2 + 4 ^ 2) = √25 = 5 H
Let’s find the acceleration module:
l a l = l F l / m;
l a l = 5/2 = 2.5 (m / s ^ 2)
Answer: 2.5