A body weighing 2 kg is lifted vertically upward to a height of 5 m with a force of 30 N. Is the work of this force equal?

Work can be found by the formula A = F * s = m * g * s, where A is work, F is force, s is distance, m is the mass of an object.
In this problem, the distance is the height h.
Thus, A = F * s = m * g * s = m * g * h = 2 kg * 10 m / s ^ 2 * 5 m = 100 J.
Answer: A = 100 J.



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