A body weighing 2 kg is thrown upward at a speed of 10 m / s. What is the lifting height and potential energy of the body at the top?

Maximum body height:
S = (V² – V0²) / 2a, where V is the final speed of the body (V = 0 m / s), V0 is the initial speed of the body (V0 = 10 m / s), and is the acceleration of the body (а = g (g – acceleration of gravity, we take g = 10 m / s²)).
S = (V² – V0²) / 2a = 10² / (2 * 10) = 100/20 = 5m.
Potential body energy:
Ep = m * g * h, where m is body weight (m = 2 kg).
Ep = m * g * h = 2 * 10 * 5 = 100 J.
Answer: The lifting height is 5 m, the potential energy is 100 J.