A body weighing 2 kg is thrown vertically downward with an initial speed of 5 m / s. What will be the kinetic energy of the body
| November 23, 2020 | education
A body weighing 2 kg is thrown vertically downward with an initial speed of 5 m / s. What will be the kinetic energy of the body 2 seconds after the start of the fall, if the resistance to movement can be neglected?
E = (mV ^ 2) / 2.
V = V0 + gt.
V = 5 + 20 = 25.
E = (2 * 625) / 2 = 625 J.
Answer: 625 J.
or
v = vo + gt = 5 + 10 * 2 = 25 m / s.
E = m * v ^ 2/2 = 2 * 25 * 25/2 = 625 J.
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