To calculate the maximum height that the thrown body could reach, we use the equality: Ek = Ep (the law of conservation of energy) and m * Vn ^ 2/2 = m * g * hx, whence hx = Vn ^ 2 / 2g.
Variables and constants: Vн – speed of throwing upwards (Vн = 3 m / s); g – acceleration due to gravity (g ≈ 10 m / s2).
Calculation: hx = Vn ^ 2 / 2g = 3 ^ 2 / (2 * 10) = 9/20 = 0.45 m.
Answer: The highest height that the thrown body has reached is 0.45 m.
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