A body weighing 2 kg is thrown vertically upward at a speed of 40 m / s. What is the potential energy
| December 11, 2020 | education
A body weighing 2 kg is thrown vertically upward at a speed of 40 m / s. What is the potential energy of the body at the top point of ascent?
Given:
m = 2 kg
v = 40 m / s
Upper lifting point
Find: Ep
Decision:
Energy conservation law: En = Ek
Ep = mv ^ 2/2
Ep = 2kg * 40 ^ 2m / s / 2 = 1600 J
Answer: En = 1600 J.
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