A body weighing 2 kg moved in a circle, and at some point it had a speed of 4 m / s. Having passed

| June 3, 2021 | education

A body weighing 2 kg moved in a circle, and at some point it had a speed of 4 m / s. Having passed a quarter of a circle, the body acquired a speed of 3 m / s. Determine the modulus of the body impulse change.

To determine the modulus of change in the momentum of a given body, we use the formula (we take into account that the velocity vector at some point is perpendicular to the velocity vector after passing a quarter circle): ΔP = √ (P ^ 2 + P1 ^ 2) = √ ((m * V) ^ 2 + (m * V1) ^ 2).

Variables: m – body weight (m = 2 kg); V – speed at some point (V = 4 m / s); V1 – the speed of the body after passing a quarter of a circle (V1 = 3 m / s).

Calculation: ΔP = √ ((m * V) ^ 2 + (m * V1) ^ 2) = √ ((2 * 4) ^ 2 + (2 * 3) ^ 2) = 10 kg * m / s.

Answer: The modulus of change in the momentum of a given body is 10 kg * m / s.



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