# A body weighing 2 kg moves evenly along a horizontal plane. In this case, the friction force

August 17, 2021 | education

| **A body weighing 2 kg moves evenly along a horizontal plane. In this case, the friction force is equal to 5N. What is the coefficient of friction?**

Since the body moves on a horizontal surface, the normal reaction force is equal to the force of gravity and the formula for calculating the friction force has the form: Ffr = μ * N = μ * Ft = μ * m * g, from where we express: μ = Ffr / (m * g).

Variables and constants: μ = Ftr / (m * g) = 5 / (2 * 10) = 0.25.

Answer: The coefficient of friction between a given body and a horizontal plane is 0.25.

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