A body weighing 2 kg thrown from a certain height vertically upwards fell to the ground at a speed of 6 m / s.

| August 10, 2021 | education

A body weighing 2 kg thrown from a certain height vertically upwards fell to the ground at a speed of 6 m / s. the potential energy of the body relative to the surface of the earth at the moment of throwing was equal to 20 J with what initial speed the body was thrown. neglect air resistance.

To calculate the initial speed of throwing the taken body up, we use the equality: Ek = Ek0 + Ep0 and m * V ^ 2/2 = m * V0 ^ 2/2 + Ep, whence we express: V0 = √ (2 * (m * V ^ 2/2 – Ep) / m).

Variables and constants: m is the mass of the body taken (m = 2 kg); V – falling speed (V = 6 m / s); Ep is the initial potential energy (Ep = 20 J).

Calculation: V0 = √ (2 * (m * V ^ 2/2 – Ep) / m) = √ (2 * (2 * 6 ^ 2/2 – 20) / 2) = 4 m / s.

Answer: The taken body was thrown upward at a speed of 4 m / s.



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