A body weighing 2 kg, thrown from a height of 250 m vertically down at a speed of 20 m / s

| September 3, 2021 | education

A body weighing 2 kg, thrown from a height of 250 m vertically down at a speed of 20 m / s, plunged into the ground to a depth of 20 cm. Determine the average force of soil resistance. Do not take into account air resistance.

To calculate the average soil resistance force, we use the formula: Acopr = ΔEk + ΔEp and Fcopr * S = m * V0 ^ 2/2 + m * g * h0 = m * (V0 ^ 2/2 + g * h0), from where we express : Fcopr = m * (V0 ^ 2/2 + g * h0) / S.

Constants and variables: m – body weight (m = 2 kg); V0 – downward throw speed (V0 = 20 m / s); g – acceleration due to gravity (g ≈ 10 m / s2); h0 – initial body height (h0 = 250 m); S is the depth of immersion in the ground (S = 20 cm = 0.2 m).

Calculation: Fcopr = m * (V0 ^ 2/2 + g * h0) / S = 2 * (20 ^ 2/2 + 10 * 250) / 0.2 = 27 * 10 ^ 3 H = 27 kN.

Answer: The average soil resistance is 27 kN.



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