A body weighing 2 kg was thrown from the surface of the earth at a speed of 6 m / s at an angle of 30 ° to the horizon.

A body weighing 2 kg was thrown from the surface of the earth at a speed of 6 m / s at an angle of 30 ° to the horizon. How much will the potential energy of the body increase when it reaches its highest point of ascent?

To find the increase in the potential energy of a thrown body, we will use the formula: ΔEp = Ep – Ep0 = m * g * hmax – 0 = m * g * V ^ 2 * sin2α / 2g = m * V ^ 2 * sin2α / 2.

Variables: m is the mass of the thrown body (m = 2 kg); V – throw speed (V = 6 m / s); α – angle to the horizon (α = 30º).

Let’s calculate: ΔEp = m * V ^ 2 * sin2α / 2 = 2 * 6 ^ 2 * (sin 30º) ^ 2/2 = 9 J.

Answer: At the highest point of ascent, the potential energy of the thrown body will increase by 9 J.