A body weighing 20 kg is lifted to a height of 50 m with the help of some force

A body weighing 20 kg is lifted to a height of 50 m with the help of some force directed vertically upward. What is the work of this force equal to?

m = 20 kg.
g = 9.8 m / s ^ 2.
h = 50 m.
h0 = 50 m.
BUT – ?
A = Δ Ep.
The work of force A, which lifts the body to a height of 50 meters, is equal to the change in its potential energy ΔEp.
Δ Еп = m * g * h – m * g * hо.
Since hо = 0, then ΔEп = m * g * h.
A = m * g * h.
A = 20 kg * 9.8 m / s ^ 2 * 50 m = 9800 J.
Answer: A = 9800 J.