A body weighing 20 kg moves in a circle with a radius of 3 m under the action of a force of 20 N.
| April 10, 2021 | education
A body weighing 20 kg moves in a circle with a radius of 3 m under the action of a force of 20 N. What is the work done by the force during 1 period of rotation?
To determine the work of the acting force for 1 period of rotation of the body, we use the formula (we take into account that in 1 period of rotation the body has traveled a path equal to the length of one circle): A = F * S = F * 2 * Π * R.
Variables: F – acting force (F = 20 N); R is the radius of the circle (R = 3 m).
Calculation: A = F * 2 * Π * R = 20 * 2 * 3.14 * 3 = 376.8 J.
Answer: For 1 period of rotation, the acting force performed work of 376.8 J.
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