A body weighing 20 kg moving at a speed of 0.3 m / s catches up with a body weighing 30 kg moving at a speed

| August 18, 2021 | education

A body weighing 20 kg moving at a speed of 0.3 m / s catches up with a body weighing 30 kg moving at a speed of 0.2 m / s what will be their total speed after inelastic interaction.

Data: m1 (mass of the first body) = 20 kg; V1 (speed of movement of the first body) = 0.3 m / s; m2 (mass of the second body) = 30 kg; V2 (speed of the second body) = 0.2 m / s; the first body was catching up with the second (the velocity vectors are directed in one direction); the interaction of bodies is inelastic.

The general speed of bodies after interaction is determined by the formula: V = (m1 * V1 + m2 * V2) / (m1 + m2).

Calculation: V = (20 * 0.3 + 30 * 0.2) / (20 + 30) = 0.24 m / s.

Answer: After inelastic interaction, the speed of the bodies will be equal to 0.24 m / s.



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