A body weighing 200 g floats in a liquid with a density twice that of the substance

A body weighing 200 g floats in a liquid with a density twice that of the substance of the floating body. What is the mass of the displaced fluid?

Since the system will be in equilibrium: Fa = Fт.
Fa is the strength of Archimedes; Fa = ρl * g * V, where ρl is the density of the fluid, g is the acceleration of gravity, V is the volume of the submerged part of the body.
Fт is the force of gravity; Ft = mt * g, where mt is the body weight (mt = 200 g = 0.2 kg).
mt * g = ρl * g * V.
V = mt / ρl. Since ρl = 2ρt, the body is immersed in a liquid by 1/2 of its volume.
Since Fa = mzh * g, where mzh is the mass of the displaced liquid, then
ρzh * g * mt / ρzh = mzh * g;
mw = mt = 0.2 kg
Answer: The mass of the displaced liquid is 0.2 kg.