A body weighing 200 g freely falls from a height of 15 m. Find the speed of the earth’s surface.

Since the body under consideration began its fall without an initial velocity, we calculate its velocity at the surface using the equality: m * V ^ 2/2 = m * g * h, whence V = √ (g * h * 2).

Constants and variables: g – gravitational acceleration (g ≈ 10 m / s2); h – fall height (h = 15 m).

Calculation: V = √ (g * h * 2) = √ (10 * 15 * 2) = 17.32 m / s.

Answer: At the surface, the body has reached a speed of 17.32 m / s.