A body weighing 200 g vibrates on a spring with a rigidity of 2000 N / m. Determine the period of body vibration.
| February 5, 2021 | education
To calculate the oscillation period of a body fixed on a spring, we will use the formula: T = 2 * Π * √ (m / k).
The values of the variables: m is the mass of the cargo (m = 200 g = 0.2 kg); k is the stiffness of the spring (k = 2000 N / m).
Calculation: T = 2 * Π * √ (m / k) = 2 * 3.14 * √ (0.2 / 2000) = 0.0628 s = 62.8 ms.
Answer: Oscillations of a body fixed on a spring occur with a period of 62.8 ms.
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