A body weighing 200g changes its coordinates according to the law: X = 3 + 4t + 5t ^ 2 (m)

A body weighing 200g changes its coordinates according to the law: X = 3 + 4t + 5t ^ 2 (m) After what time interval after the start of movement, the body will have an impulse of 2Ns?

To find the duration of body movement before reaching an impulse of 2 N * s, we will use the formula: P = m * V = m * x (t) ‘.

Variables and functions: P – required impulse (P = 2 N * s); m – body weight (m = 200 g = 0.2 kg); the law of motion x (t) = 3 + 4t + 5t ^ 2.

Calculation: 2 = 0.2 * (3 + 4t + 5t ^ 2) ‘.

2 = 0.2 * (0 + 4 + 10t).

2 = 0.8 + 2t.

2t = 2 – 0.8 = 1.2 and t = 1.2 / 2 = 0.6 s.

Answer: The body will have an impulse equal to 2 N * s in 0.6 s.