A body weighing 200g falls vertically downward with an acceleration of 9m / s2.

A body weighing 200g falls vertically downward with an acceleration of 9m / s2. What is the average force of air resistance?

Given:

m = 200 grams = 0.2 kilograms is the mass of a body falling vertically downward;

g = 10 m / s ^ 2 – acceleration of gravity;

a = 9 m / s ^ 2 – the acceleration with which the body falls.

It is required to determine Fsopr. (Newton) – the average force of air resistance.

The body falls under the influence of two forces: the force of gravity, directed downward, and the force of air resistance, directed upward. Then, according to Newton’s second law:

F gravity – F = m * a;

m * g – Fc. = m * a;

Fc. = m * g – m * a = m * (g – a) = 0.2 * (10 – 9) = 0.2 * 1 = 0.2 Newtons.

Answer: the force of air resistance is 0.2 Newton.