A body weighing 250 g was thrown vertically upward at a speed of 15 m / s.

A body weighing 250 g was thrown vertically upward at a speed of 15 m / s. Determine its potential energy at the highest point of the trajectory and the highest height.

m = 250 g = 0.25kg
V = 15m / s
g = 10 m / s2
En-?
h-?
The body will move vertically upward until all of its kinetic energy is converted into potential. Ek = En. Ek = m * V ^ 2/2; Ep = 0.25kg * (15m / s) ^ 2/2 = 28.125 J.En = m * g * h; m * V ^ 2/2 = m * g * h; h = m * V ^ 2/2 * m * g = V ^ 2/2 * g; h = (15m / s) ^ 2/2 * 10 m / s2 = 225/20 = 11.25 m. At an altitude of 11.25 m, the body will stop.
Answer: Ep = 28.125 J, the maximum lifting height is 11.25 m.