A body weighing 3 kg falls to the ground from a height of 3 m with an acceleration of 6 m / s. How much will his impulse change?
| January 18, 2021 | education
To calculate the change in momentum of a falling body, we apply the formula: ΔР = m * ΔV = m * √ (2a * h).
Constants and variables: m (mass of the falling body) = 3 kg; a (acceleration) = 6 m / s2; h (starting height) = 3 m.
Calculation: P = m * √ (2a * h) = 3 * √ (2 * 6 * 3) = 18 N * s.
Answer: At the moment of the fall, the momentum of the body increased by 18 N * s.
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