A body weighing 3 kg moves in a straight line in one direction under the action of a constant force equal
| May 2, 2021 | education
A body weighing 3 kg moves in a straight line in one direction under the action of a constant force equal to the modulus of 5 H. Determine the modulus of the body’s impulse change in 6 s.
To find the modulus of change in the impulse of a taken body in 6 seconds of accelerated movement, we use the formula: ΔР = m * (Vк – Vн) = m * (V0 + a * t1 – V0 * a * t0) = m * a * t1 = m * (F / m) * t1 = F * t1 (impulse of force).
Variables: F – modulus of the acting force (F = 5 N); t1 – movement time (t1 = 6 s).
Calculation: ΔР = F * t1 = 5 * 6 = 30 kg * m / s.
Answer: the modulus of the impulse change is 30 kg * m / s.
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