A body weighing 4 kg rises to a height of 10 m. at the same time, work A = 550 J is performed.

A body weighing 4 kg rises to a height of 10 m. at the same time, work A = 550 J is performed. what is the speed at the end point?

To find the speed of the body being lifted at the end point, we will use the formula: А = ΔЕ = ΔЕk + ΔЕп = m * V ^ 2/2 + m * g * h, whence we express: m * V ^ 2/2 = A – m * g * h and V = √ (2 * (A – m * g * h) / m).

Variables and constants: A – perfect work (A = 550 J); m – body weight (m = 4 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h – end point height (h = 10 m).

Calculation: V = √ (2 * (A – m * g * h) / m) = √ (2 * (550 – 4 * 10 * 10) / 4) = 8.66 m / s.

Answer: At the end point, the lifted body had a speed of 8.66 m / s.