A body weighing 400 g freely falls from a height of 2 m. Find the kinetic energy of the body

A body weighing 400 g freely falls from a height of 2 m. Find the kinetic energy of the body at the moment of impact on the ground.

Initial data: m (body weight) = 400 g = 0.4 kg; h (height from which the body fell) = 2 m, the body was free to fall.

Constants: a (acceleration of a body during a fall) = g (acceleration of gravity) = 10 m / s ^ 2.

At the moment the body hits the ground, all of its initial potential energy will completely transform into kinetic (energy conservation law) and the equality is true: Ek = En = m * g * h.

Let’s calculate: Ek = 0.4 * 10 * 2 = 8 J.

Answer: At the moment of impact on the ground, the kinetic energy of the body was 8 J.