# A body weighing 4kg stops under the action of a friction force equal to 24H.

December 27, 2020 | education

| **A body weighing 4kg stops under the action of a friction force equal to 24H. Find the acceleration of the body? Formulate 2 Newton’s Law.**

m = 4 kg.

F = 24 N.

a -?

Let’s write 2 Newton’s law: F = m * a, where F is the force or the resultant force that acts on the body, m is the mass of the body, and is the acceleration of the body.

a = F / m.

a = 24 N / 4 kg = 6 m / s ^ 2.

2 Newton’s law: the acceleration of a body a is directly proportional to the force F, which acts on the body, and inversely to the mass of the body m: a = F / m.

Answer: the body will move with acceleration a = 6 m / s ^ 2.

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