A body weighing 5 kg is lifted with an acceleration of 2 m / s2. Determine the work of the force during

A body weighing 5 kg is lifted with an acceleration of 2 m / s2. Determine the work of the force during the first 5 seconds.

To find the work of the force applied to the body, we use the formula: A = F * h = (m * (g + a)) * (a * t ^ 2/2).

Variables and constants m – mass of the lifted body (m = 5 kg); g – acceleration due to gravity (g ≈ 10 m / s2); a – acceleration (a = 2 m / s2); t is the duration of the rise (t = 5 s).

Calculation: A = m * (g + a) * a * t ^ 2/2 = 5 * (10 + 2) * 2 * 5 ^ 2/2 = 1.5 kJ (1.5 * 10 ^ 3 J) …

Answer: During the first 5 seconds, the force applied to the body did a work of 1.5 kJ.