A body weighing 5 kg with the help of a rope begins to be lifted uniformly upwards. To what height was the load

A body weighing 5 kg with the help of a rope begins to be lifted uniformly upwards. To what height was the load lifted in 3 s, if the force acting on the rope is 63.3 N?

Data: mg – weight of the lifted load (mg = 5 kg); t is the duration of the accelerated rise (t = 3 s); F is the force acting on the rope (F = 63.3 N).

Const: g – acceleration due to gravity (g ≈ 9.8 m / s2).

1) Acceleration of the load: a = Fр / m = (F – m * g) / m = (63.3 – 5 * 9.8) / 5 = 2.86 m / s2.

2) Lift height: h = S = 0.5 * a * t ^ 2 = 0.5 * 2.86 * 3 ^ 2 = 12.87 m.

Answer: In 3 seconds, the load was quickly lifted to a height of 12.87 m.