A body weighing 50 kg under the action of a force of 200 N moves uniformly on a flat road. What is the coefficient of friction?

Given:

m = 50 kilograms – body weight;

F = 200 Newton – the force acting on the body;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine the coefficient of friction k.

Since, according to the condition of the problem, the body moves uniformly, then according to Newton’s first law:

F friction = F;

k * N = F;

k * m * g = F;

k = F / (m * g) = 200 / (50 * 10) = 200/500 = 0.4.

Answer: The coefficient of friction is 0.4.