A body weighing 50 kilograms under the action of a force of 200 Newtons moves uniformly along

A body weighing 50 kilograms under the action of a force of 200 Newtons moves uniformly along a flat road. What is the coefficient of friction?

m = 50 kg.

F = 200 N.

g = 9.8 m / s ^ 2.

μ -?

According to 1 Newton’s law: a body is in a state of rest or uniform rectilinear motion if no forces act on it or the action of forces is compensated.

When the body moves, the force F with which it is pulled is compensated by the friction force Ffr.

F = Ftr.

The friction force Ffr is determined by the formula:

m = 50 kg.

F = 200 N.

g = 9.8 m / s ^ 2.

μ -?

According to 1 Newton’s law: a body is in a state of rest or uniform rectilinear motion if no forces act on it or the action of forces is compensated.

When the body moves, the force F with which it is pulled is compensated by the friction force Ffr.

F = Ftr.

The friction force Ffr is determined by the formula: Ffr = μ * m * g.

F = μ * m * g.

μ = F / m * g.

μ = 200 N / 50 kg * 9.8 m / s ^ 2 = 0.4.

Answer: the coefficient of friction is μ = 0.4.