A body weighing 500 g falls with an acceleration of 8 m / s2. What is the average air resistance force?

m = 500 g = 0.5 kg.

g = 9.8 m / s ^ 2.

a = 8 m / s ^ 2.

Fsopr -?

The body that falls is affected by 2 forces: the gravity force m * g, directed vertically downward, and the air resistance force Fcopr, directed in the opposite direction of motion, vertically upward.

Let’s write 2 Newton’s law: m * a = m * g – Fcomp.

Fcopr = m * g – m * a.

Fcopr = m * (g – a).

Fcopr = 0.5 kg * (9.8 m / s ^ 2 – 8 m / s ^ 2) = 0.9 N.

Answer: the body is affected by the air resistance force Fcopr = 0.9 N.