A body weighing 500 g is acted upon for 5 s by a force of 0.2 N. What speed does the body

A body weighing 500 g is acted upon for 5 s by a force of 0.2 N. What speed does the body acquire and what path will it take during this time?

m = 0.2 kg.
V0 = 0 m / s.
t = 5 s.
F = 0.1 N.
V -?
S -?
According to 2 Newton’s laws, the acceleration of a body a is directly proportional to the force F, which acts on the body, and inversely proportional to the mass of the body m: a = F / m.
The acceleration of the body a shows how quickly the body’s speed changes over time. The acceleration of the body a is determined by the formula: a = (V – V0) / t, where V, V0 are the final and initial velocity of the body, t is the time of the velocity change.
F / m = (V – V0) / t.
Since V0 = 0 m / s, the formula will take the form: F / m = V / t.
V = F * t / m.
V = 0.1 N * 5 s / 0.2 kg = 2.5 m / s.
S = V2 / 2 * a = m * V2 / 2 * F.
S = 0.2 kg * (2.5 m / s) 2/2 * 0.1 H = 6.25 m.
Answer: V = 2.5 m / s, S = 6.25 m.



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