A body weighing 500 g was thrown vertically upward with an initial velocity of 10 m / s. At the end of the flight
A body weighing 500 g was thrown vertically upward with an initial velocity of 10 m / s. At the end of the flight, when it hit the ground, an amount of heat of 15 J. was released. What work has been done by the friction force against the air during the entire flight time?
To calculate the work of the friction force against air for the entire duration of the fall, we use the equality: Ek = Atr + Q, whence we express: Atr = Ek – Q = m * Vn ^ 2/2 – Q.
Variables and constants: m is the mass of the thrown body (m = 500 g = 0.5 kg); Vн – initial speed of throw (Vн = 10 m / s); Q is the released heat (Q = 15 J).
Calculation: Atr = m * Vn ^ 2/2 – Q = 0.5 * 10 ^ 2/2 – 15 = 10 J.
Answer: For the entire time of the flight of the thrown body, the frictional force against the air did a work of 10 J.