A body weighing 60 kg moves under the action of two forces: the first of 60 N is opposite to the displacement

A body weighing 60 kg moves under the action of two forces: the first of 60 N is opposite to the displacement, and the second of 150 N is directed at an angle of 60 ° to the displacement. Accelerating this body

Given:

m = 60 kg – body weight;

F1 = 60 N – the value of the first force opposite to the displacement of the body;

F2 = 150 N – the value of the second force, in the direction of movement of the body at an angle n;

n = 60 degrees.

It is required to find the acceleration of the body a (m / s ^ 2).

Let us find the resultant forces F:

F = F2 * cos (n) – F1 = 150 * cos (60) – 60 = 150 * 0.5 – 60 = 75 – 60 = 15 Newtons.

a = F / m = 15/60 = 0.25 m / s ^ 2.

Answer: the acceleration of the body is 0.25 m / s ^ 2.