A body weighing 7 kg is acted upon by forces of 16 N and 30 N, directed in different

A body weighing 7 kg is acted upon by forces of 16 N and 30 N, directed in different directions. Find the acceleration with which the body moves.

According to Newton’s second law:

F = m * a, where F is the resultant force (N), m is the mass of the body (m = 7 kg), and is the acceleration of the body.

If F1 and F2 point in opposite directions:

F = F1 + F2, where F1 = 16 N, F2 = 30 N.

F = -F1 + F2 = -16 + 30 = 14 N.

If F1 and F2 are directed at 90º to each other:

F² = F1² + F2².

F = sqrt (F1² + F2²) = sqrt (16² + 30²) = sqrt (1156) = 34 N.

a1 = F / m = 14/7 = 2 m / s².

a2 = F / m = 34/7 = 4.86 m / s².

Answer: The acceleration of the body is 2 m / s²; 4.86 m / s².



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